Factorise :
a2(b + c) - (b + c)3
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Given,
= (b + c)[a2 - (b + c)2]
= (b + c)(a + b + c)[a - (b + c)]
= (b + c)(a + b + c)(a - b - c).
Hence, a2(b + c) - (b + c)3 = (b + c)(a + b + c)(a - b - c).
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