Factorise : a 6 - b 6

Given, a 6 - b 6 = (a 3 ) 2 - (b 3 ) 2 = (a 3 + b 3 )(a 3 - b 3 ) = (a + b)(a 2 - ab + b 2 )(a - b)(a 2 + ab + b 2 ) = (a + b)(a - b)(a 2 - ab + b 2 )(a 2 + ab + b 2 ). Hence, a 6 - b 6 = (a + b)(a - b)(a 2 - ab + b 2 )(a 2 + ab + b 2 ).

Mathematics

Factorise :
a⁶ - b⁶

Factorisation

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Answer

Given,

a⁶ - b⁶

= (a³)² - (b³)²

= (a³ + b³)(a³ - b³)

= (a + b)(a² - ab + b²)(a - b)(a² + ab + b²)

= (a + b)(a - b)(a² - ab + b²)(a² + ab + b²).

Hence, a⁶ - b⁶ = (a + b)(a - b)(a² - ab + b²)(a² + ab + b²).

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Mathematics

Factorise :
a⁶ - b⁶

Factorisation

Answer

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Mathematics

Factorise :a6 - b6

Factorisation

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Related Questions

Factorise :(x - y)3 - 8x3

Factorise :a6 - 7a3 - 8

Factorise :a3 - 27b3 + 2a2b - 6ab2

Factorise :
a⁶ - b⁶

Factorise :
(x - y)³ - 8x³

Factorise :
a⁶ - 7a³ - 8

Factorise :
a³ - 27b³ + 2a²b - 6ab²