Factorise by grouping method : a 2 x 2 + (ax 2 + 1)x + a

Given, a 2 x 2 + (ax 2 + 1)x + a = a 2 x 2 + ax 3 + x + a = a 2 x 2 + ax 3 + a + x = ax 2 (a + x) + 1(a + x) = (a + x)(ax 2 + 1). Hence, a 2 x 2 + (ax 2 + 1)x + a = (a + x)(ax 2 + 1).

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Mathematics

Factorise by grouping method :
a²x² + (ax² + 1)x + a

Factorisation

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Answer

Given,

a²x² + (ax² + 1)x + a

= a²x² + ax³ + x + a

= a²x² + ax³ + a + x

= ax²(a + x) + 1(a + x)

= (a + x)(ax² + 1).

Hence, a²x² + (ax² + 1)x + a = (a + x)(ax² + 1).

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Mathematics

Factorise by grouping method :
a²x² + (ax² + 1)x + a

Factorisation

Answer

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Mathematics

Factorise by grouping method :a2x2 + (ax2 + 1)x + a

Factorisation

Answer

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