Mathematics
Answer
(i) 27y3 + 125z3
[∵ x3 + y3 = (x + y)(x2 - xy + y2)]
⇒ 27y3 + 125z3 = (3y)3 + (5z)3
Putting x = 3y, y = 5z
R.H.S = (x + y)(x2 - xy + y2)
= (3y + 5z)[(3y)2 - (3y)(5z) + (5z)2]
= (3y + 5z)(9y2 - 15yz + 25z2)
Hence, 27y3 + 125z3 = (3y + 5z)(9y2 - 15yz + 25z2)
(ii) 64m3 - 343n3
[∵ a3 - b3 = (a - b)(a2 + ab + b2)]
⇒ 64m3 - 343n3 = (4m)3 - (7n)3
Putting a = 4m, b = 7n
R.H.S = (a - b)(a2 + ab + b2)
= (4m - 7n)[(4m)2 + (4m)(7n) + (7n)2]
= (4m - 7n)(16m2 + 28mn + 49n2)
Hence, 64m3 - 343n3 = (4m - 7n)(16m2 + 28mn + 49n2)