Factorise the following:
10a(2p + q)3 - 15b(2p + q)2 + 35(2p + q)
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H.C.F. of 10a(2p + q)3, 15b(2p + q)2 and 35(2p + q) is 5(2p + q).
∴ 10a(2p + q)3 - 15b(2p + q)2 + 35(2p + q) = 5(2p + q)[2a(2p + q)2 - 3b(2p + q) + 7].
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6(x + 2y)3 + 8(x + 2y)2
14(a - 3b)3 - 21p(a - 3b)
x(x2 + y2 - z2) + y(-x2 - y2 + z2) - z(x2 + y2 - z2).
x2 + xy - x - y