Factorise the following: 27x 3 y 3 - 8

27x 3 y 3 - 8 = (3xy) 3 - (2) 3 . We know that, a 3 - b 3 = (a - b)(a 2 + ab + b 2 ) (3xy) 3 - (2) 3 = (3xy - 2)[(3xy) 2 + 3xy.2 + 2 2 ] = (3xy - 2)(9x 2 y 2 + 6xy + 4). Hence, 27x 3 y 3 - 8 = (3xy - 2)(9x 2 y 2 + 6xy + 4).

Mathematics

Factorise the following:
27x³y³ - 8

Factorisation

14 Likes

Answer

27x³y³ - 8 = (3xy)³ - (2)³.

We know that,

a³ - b³ = (a - b)(a² + ab + b²)

(3xy)³ - (2)³ = (3xy - 2)[(3xy)² + 3xy.2 + 2²]

= (3xy - 2)(9x²y² + 6xy + 4).

Hence, 27x³y³ - 8 = (3xy - 2)(9x²y² + 6xy + 4).

Answered By

9 Likes

Mathematics

Factorise the following:
27x³y³ - 8

Factorisation

Answer

Related Questions

Factorise the following:
x² + x⁵

Factorise the following:
32x⁴ - 500x

Factorise the following:
27(x + y)³ + 8(2x - y)³

Factorise the following:
a³ + b³ + a + b

Mathematics

Factorise the following:27x3y3 - 8

Factorisation

Answer

Related Questions

Factorise the following:x2 + x5

Factorise the following:32x4 - 500x

Factorise the following:27(x + y)3 + 8(2x - y)3

Factorise the following:a3 + b3 + a + b

Factorise the following:
27x³y³ - 8

Factorise the following:
x² + x⁵

Factorise the following:
32x⁴ - 500x

Factorise the following:
27(x + y)³ + 8(2x - y)³

Factorise the following:
a³ + b³ + a + b