Factorise the following: 3a(x 2 + y 2 ) + 6b(x 2 + y 2 ).

H.C.F. of 3a(x 2 + y 2 ) and 6b(x 2 + y 2 ) is 3(x 2 + y 2 ). ∴ 3a(x 2 + y 2 ) + 6b(x 2 + y 2 ) = 3(x 2 + y 2 )(a + 2b).

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H.C.F. of 3a(x² + y²) and 6b(x² + y²) is 3(x² + y²).

∴ 3a(x² + y²) + 6b(x² + y²) = 3(x² + y²)(a + 2b).

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