Factorise the following:
3x2y - 3xy + 12x - 12.
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= 3(x2y - xy + 4x - 4)
= 3[xy(x - 1) + 4(x - 1)]
= 3(x - 1)(xy + 4)
Hence, 3x2y - 3xy + 12x - 12 = 3(x - 1)(xy + 4).
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(ax + by)2 + (bx - ay)2.
a3 + ab(1 - 2a) - 2b2.
a2b + ab2 - abc - b2c + axy + bxy.
ax2 - bx2 + ay2 - by2 + az2 - bz2.