Mathematics
Factorise the following:
5ph - 10qk + 2rph - 4qrk
Factorisation
31 Likes
Answer
5ph - 10qk + 2rph - 4qrk
= 5(ph - 2qk) + 2r(ph - 2qk)
= (5 + 2r)(ph - 2qk).
Hence, 5ph - 10qk + 2rph - 4qrk = (5 + 2r)(ph - 2qk).
Answered By
15 Likes
|
Factorise the following:
5ph - 10qk + 2rph - 4qrk
31 Likes
5ph - 10qk + 2rph - 4qrk
= 5(ph - 2qk) + 2r(ph - 2qk)
= (5 + 2r)(ph - 2qk).
Hence, 5ph - 10qk + 2rph - 4qrk = (5 + 2r)(ph - 2qk).
Answered By
15 Likes