Mathematics
Factorise the following:
64x3 + 1
Factorisation
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Answer
64x3 + 1 = (4x)3 + (1)3.
We know that,
a3 + b3 = (a + b)(a2 - ab + b2)
∴ (4x)3 + (1)3 = (4x + 1)[(4x)2 - 4x.1 + 12]
= (4x + 1)(16x2 - 4x + 1).
Hence, 64x3 + 1 = (4x + 1)(16x2 - 4x + 1).
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