Factorise the following:
a(a - 2b - c) + 2bc
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= a2 - 2ab - ac + 2bc
= a2 - ac - 2ab + 2bc
= a(a - c) - 2b(a - c)
= (a - 2b)(a - c).
Hence, a(a - 2b - c) + 2bc = (a - 2b)(a - c).
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9a2y - 9ay + 6a - 6
1 - a - b + ab
x2 + xy(1 + y) + y3
y2 - xy(1 - x) - x3