Factorise :
x2 + 3x + 2 + ax + 2a
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Given,
= x2 + 3x + 2 + a(x + 2)
= x2 + 2x + x + 2 + a(x + 2)
= x(x + 2) + 1(x + 2) + a(x + 2)
= (x + 2)(x + 1 + a).
Hence, x2 + 3x + 2 + ax + 2a = (x + 2)(x + 1 + a).
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