Factorise : x 2 + y 2 + x + y + 2xy

Given, x 2 + y 2 + x + y + 2xy = x 2 + y 2 + 2xy + x + y = (x + y) 2 + (x + y) = (x + y)(x + y + 1). Hence, x 2 + y 2 + x + y + 2xy = (x + y)(x + y + 1).

Mathematics

Factorise :
x² + y² + x + y + 2xy

Factorisation

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Answer

Given,

x² + y² + x + y + 2xy

= x² + y² + 2xy + x + y

= (x + y)² + (x + y)

= (x + y)(x + y + 1).

Hence, x² + y² + x + y + 2xy = (x + y)(x + y + 1).

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Mathematics

Factorise :x2 + y2 + x + y + 2xy

Factorisation

Answer

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