Factorise : x 4 + y 4 - 27x 2 y 2

Given, x 4 + y 4 - 27x 2 y 2 = x 4 + y 4 - 2x 2 y 2 - 25x 2 y 2 = (x 2 - y 2 ) 2 - (5xy) 2 = (x 2 - y 2 + 5xy)(x 2 - y 2 - 5xy). Hence, x 4 + y 4 - 27x 2 y 2 = (x 2 - y 2 + 5xy)(x 2 - y 2 - 5xy).

Mathematics

Factorise :
x⁴ + y⁴ - 27x²y²

Factorisation

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Answer

Given,

x⁴ + y⁴ - 27x²y²

= x⁴ + y⁴ - 2x²y² - 25x²y²

= (x² - y²)² - (5xy)²

= (x² - y² + 5xy)(x² - y² - 5xy).

Hence, x⁴ + y⁴ - 27x²y² = (x² - y² + 5xy)(x² - y² - 5xy).

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Mathematics

Factorise :
x⁴ + y⁴ - 27x²y²

Factorisation

Answer

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Factorise :x4 + y4 - 27x2y2

Factorisation

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