Mathematics
Factorize:
a2(b + c) - (b + c)3
Factorisation
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Answer
Given,
⇒ a2(b + c) - (b + c)3
⇒ (b + c)[a2 - (b + c)2]
⇒ (b + c)(a + b + c)(a - b - c).
Hence, a2(b + c) - (b + c)3 = (b + c)(a + b + c)(a - b - c).
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Factorize:
a2(b + c) - (b + c)3
1 Like
Given,
⇒ a2(b + c) - (b + c)3
⇒ (b + c)[a2 - (b + c)2]
⇒ (b + c)(a + b + c)(a - b - c).
Hence, a2(b + c) - (b + c)3 = (b + c)(a + b + c)(a - b - c).
Answered By
2 Likes