Mathematics
In a family of 3 children, the probability of having at least one boy is:
Probability
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Answer
The sample space is: {BBB, BBG, BGB, GBB, BGG, GBG, GGB, GGG}
The total number of possible combinations = 8
Let E be the event of having at least one boy, then
E = {BBB, BBG, BGB, GBB, BGG, GBG, GGB}
The number of favorable outcomes to the event E = 7
∴ P(E) =
Hence, option 4 is the correct option.
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