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Mathematics

Farida bought some bags of cement, each weighing 49.8 kg. If the total weight of all the bags is 1792.8 kg, how many bags did she buy?

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Answer

Weight of each bag = 49.8 kg

Total weight of all the bags = 1792.8 kg

Number of bags = 1792.849.8\dfrac{1792.8}{49.8}

Multiplying both the numerator and denominator by 10, we get:

Number of bags = 1792.8×1049.8×10=17928498\dfrac{1792.8 \times 10}{49.8 \times 10} = \dfrac{17928}{498}

By actual division, we have:

498) 17936498) 17928‾498−1494‾498) )12988498) )−2988‾498) 1792×\begin{array}{l} \phantom{498)\space 179}36 \ 498\overline{\smash{\big)}\space 17928} \ \phantom{498}\underline{-1494} \ \phantom{498)\space )1}2988 \ \phantom{498)\space)}\underline{-2988} \ \phantom{498)\space 1792}\times \end{array}

Hence, Farida bought 36 bags of cement.

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