Mathematics
In the figure, four faces of the solid are shaded. The shaded area is :
100 cm2
150 cm2
200 cm2
300 cm2
Mensuration
2 Likes
Answer
Given,
Total height = 10 cm
Inner vertical step height = 6 cm
So lower height = 10 - 6 = 4 cm
Total front width = 10 cm
Top block width = 5 cm
Bottom block width = 5 cm.
Calculating the area of top face of the tall block,
Area of rectangle = length × breadth
= 5 × 10 = 50 cm2.
Calculating the area of top face of the lower block,
Area of rectangle = 5 × 10 = 50 cm2.
Calculating the vertical inner face (step)
Length = 6 cm
Breadth = 10 cm
Area = 6 × 10 = 60 cm2.
Calculating the area of bottom side outer face,
Length = 10 cm
Breadth = 4 cm
Area = 4 × 10 = 40 cm2.
Total shaded area = 50 + 50 + 60 + 40
= 200 cm2.
Hence, option 3 is the correct option.
Answered By
3 Likes
Related Questions
The volume of a cuboid of dimensions x, y and z is V and its surface area is S. The value of is :
If a cube has surface area S and volume V, then the volume of the cube of surface area 2S is :
2V
In the figure, there are fifty, 500 rupee notes in the bundle. Volume of the bundle is 98 cm3, length = 14 cm and breadth = 7 cm. The thickness of 1 note is :
1 mm
0.1 mm
2 mm
0.2 mm
In the figure (i) below, a cuboid is shown. The surface area of three faces are marked as x, y and z. In figure (ii), two such cuboids are stacked. Find the surface area of the new cuboid in figure (ii) in terms of x, y and z.
