Fill in the boxes by the symbol < or > to make the given statements true:

(i) $\dfrac{5}{11} \boxed{\phantom{653}} \dfrac{3}{7}$

(ii) $\dfrac{8}{15}$ $\boxed{\phantom{653}}$ $\dfrac{3}{5}$

(iii) $\dfrac{11}{14}$ $\boxed{\phantom{653}}$ $\dfrac{29}{35}$

(iv) $\dfrac{13}{27}$ $\boxed{\phantom{653}}$ $\dfrac{15}{48}$

(i) $\dfrac{5}{11}$ and $\dfrac{3}{7}$

By cross multiplication,

5 × 7 = 35 and 11 × 3 = 33

Since 35 > 33, therefore, $\dfrac{5}{11} \gt \dfrac{3}{7}$.

Hence, $\dfrac{5}{11} \gt \dfrac{3}{7}$.

(ii) $\dfrac{8}{15}$ and $\dfrac{3}{5}$

By cross multiplication,

8 × 5 = 40 and 15 × 3 = 45

Since 40 < 45, therefore, $\dfrac{8}{15} \lt \dfrac{3}{5}$.

Hence, $\dfrac{8}{15} \lt \dfrac{3}{5}$.

(iii) $\dfrac{11}{14}$ and $\dfrac{29}{35}$

LCM of 14 and 35 = 70.

$\Rightarrow \dfrac{11}{14} = \dfrac{11 \times 5}{14 \times 5} = \dfrac{55}{70} \\[1em] \Rightarrow \dfrac{29}{35} = \dfrac{29 \times 2}{35 \times 2} = \dfrac{58}{70}$

As 55 < 58,

$\dfrac{55}{70} \lt \dfrac{58}{70} \Rightarrow \dfrac{11}{14} \lt \dfrac{29}{35}$.

Hence, $\dfrac{11}{14} \lt \dfrac{29}{35}$.

(iv) $\dfrac{13}{27}$ and $\dfrac{15}{48}$

By cross multiplication,

13 × 48 = 624 and 27 × 15 = 405

Since 624 > 405, therefore, $\dfrac{13}{27} \gt \dfrac{15}{48}$.

Hence, $\dfrac{13}{27} \gt \dfrac{15}{48}$.