Fill in the blanks:

(i) Additive inverse of $\dfrac{-5}{-12}$ = …………… .

(ii) $\dfrac{-5}{-12}$ + its additive inverse = …………… .

(iii) If $\dfrac{a}{b}$ is the additive inverse of $\dfrac{-c}{d}$, then $\dfrac{-c}{d}$ is the additive inverse of …………… .
And, so $\dfrac{a}{b} + \dfrac{-c}{d} = \dfrac{-c}{d} + \dfrac{a}{b}$ = …………… .

(i) Additive inverse of $\dfrac{-5}{-12} = -\dfrac{5}{12}$.

(ii) $\dfrac{-5}{-12}$ + its additive inverse = 0

(iii) If $\dfrac{a}{b}$ is the additive inverse of $\dfrac{-c}{d}$, then $\dfrac{-c}{d}$ is the additive inverse of $\dfrac{a}{b}$.
And, so $\dfrac{a}{b} + \dfrac{-c}{d} = \dfrac{-c}{d} + \dfrac{a}{b} = 0$.

Explanation

(i) $\dfrac{-5}{-12} = \dfrac{5}{12}$
Additive inverse of $\dfrac{5}{12} = -\dfrac{5}{12}$

(ii) $\dfrac{5}{12} + \Big(-\dfrac{5}{12}\Big)$

$= \dfrac{5 - 5}{12} \\[1em] = 0$

(iii) The sum of number and its additive inverse = Additive identity.