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Mathematics

Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.

14,14-\dfrac{1}{4}, \dfrac{1}{4}

Polynomials

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Answer

For given roots,

Quadratic equation : x2 - (Sum of roots)x + (Product of roots) = 0

Substituting values we get :

x2(14)x+(14)=0x2+x4+14=04x2+x+14=04x2+x+1=0.\Rightarrow x^2 - \Big(-\dfrac{1}{4}\Big)x + \Big(\dfrac{1}{4}\Big) = 0 \\[1em] \Rightarrow x^2 + \dfrac{x}{4} + \dfrac{1}{4} = 0 \\[1em] \Rightarrow \dfrac{4x^2 + x + 1}{4} = 0 \\[1em] \Rightarrow 4x^2 + x + 1 = 0.

Hence, required quadratic equation is 4x2 + x + 1 = 0.

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