Find the additive inverse of:

$\dfrac{16}{7}$

To find the additive inverse of any rational number, change its sign.

Changing the sign of $\dfrac{16}{7}$, we get $\dfrac{-16}{7}$.

[Check : $\dfrac{16}{7} + \dfrac{-16}{7} = \dfrac{0}{7} = 0$]

Hence, the additive inverse of $\mathbf{\dfrac{16}{7} \text{ is } \dfrac{-16}{7}}$.