Find the altitude of an equilateral triangle of side 5 cm.

Question

KnowledgeBoat · Accepted Answer

In △ ABC, Draw altitude AD perpendicular to BC. In an equilateral triangle, the altitude also acts as the median (bisecting the base). ∴ BD = × BC = In right angled △ABD, Using Pythagoras theorem, Hypotenuse2 = Perpendicular2 + Base2 ⇒ AB2 = AD2 + BD2 Hence, the altitude is 7.5 cm.

Mathematics

Find the altitude of an equilateral triangle of side 5 cm.

Pythagoras Theorem

Related Questions

From the given figure, find the area of trapezium ABCD.

In a rhombus ABCD, prove that AC² + BD² = 4AB².

In △ABC, ∠B = 90° and D is the mid-point of BC. Prove that
(i) AC² = AD² + 3 CD²
(ii) BC² = 4 (AD² - AB²)

Mathematics

Find the altitude of an equilateral triangle of side 5 cm.

Pythagoras Theorem

Related Questions

From the given figure, find the area of trapezium ABCD.

In a rhombus ABCD, prove that AC2 + BD2 = 4AB2.

In △ABC, ∠B = 90° and D is the mid-point of BC. Prove that(i) AC2 = AD2 + 3 CD2(ii) BC2 = 4 (AD2 - AB2)

In a rhombus ABCD, prove that AC² + BD² = 4AB².

In △ABC, ∠B = 90° and D is the mid-point of BC. Prove that
(i) AC² = AD² + 3 CD²
(ii) BC² = 4 (AD² - AB²)