Mathematics
Find the approximate sum to the nearest ten :
(i) (72 + 37)
(ii) (264 + 348)
(iii) (2,538 + 6,274)
(iv) (4,782 + 2,345)
Number System
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Answer
(i) (72 + 37)
Round 72 to the nearest ten: The units digit is 2, so it rounds down to 70.
Round 37 to the nearest ten: The units digit is 7, so it rounds up to 40.
Approximate sum: 70 + 40 = 110
Hence, the approximate sum = 110.
(ii) (264 + 348)
Round 264 to the nearest ten: The units digit is 4, so it rounds down to 260.
Round 348 to the nearest ten: The units digit is 8, so it rounds up to 350.
Approximate sum: 260 + 350 = 610
Hence, the approximate sum = 610.
(iii) (2,538 + 6,274)
Round 2,538 to the nearest ten: The units digit is 8, so it rounds up to 2,540.
Round 6,274 to the nearest ten: The units digit is 4, so it rounds down to 6,270.
Approximate sum: 2,540 + 6,270 = 8,810
Hence, the approximate sum = 8,810.
(iv) (4,782 + 2,345)
Round 4,782 to the nearest ten: The units digit is 2, so it rounds down to 4,780.
Round 2,345 to the nearest ten: The units digit is 5, so it rounds up to 2,350.
Approximate sum: 4,780 + 2,350 = 7,130
Hence, the approximate sum = 7,130.
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Related Questions
Round each of the following numbers to the nearest hundred :
(i) 925
(ii) 6,854
(iii) 41,263
(iv) 27,861
(v) 5,549
Round each of the following numbers to the nearest thousand :
(i) 7,386
(ii) 34,276
(iii) 23,804
(iv) 76,540
Find the approximate sum to the nearest hundred :
(i) (347 + 476)
(ii) (654 + 247)
(iii) (5,240 + 3,421)
(iv) (9,483 + 6,572)
Find the approximate sum to the nearest thousand :
(i) (43,728 + 36,275)
(ii) (37,804 + 22,475)
(iii) (6,785 + 2,476)