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Mathematics

Find the approximate sum to the nearest ten :

(i) (72 + 37)

(ii) (264 + 348)

(iii) (2,538 + 6,274)

(iv) (4,782 + 2,345)

Number System

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Answer

(i) (72 + 37)

Round 72 to the nearest ten: The units digit is 2, so it rounds down to 70.

Round 37 to the nearest ten: The units digit is 7, so it rounds up to 40.

Approximate sum: 70 + 40 = 110

Hence, the approximate sum = 110.

(ii) (264 + 348)

Round 264 to the nearest ten: The units digit is 4, so it rounds down to 260.

Round 348 to the nearest ten: The units digit is 8, so it rounds up to 350.

Approximate sum: 260 + 350 = 610

Hence, the approximate sum = 610.

(iii) (2,538 + 6,274)

Round 2,538 to the nearest ten: The units digit is 8, so it rounds up to 2,540.

Round 6,274 to the nearest ten: The units digit is 4, so it rounds down to 6,270.

Approximate sum: 2,540 + 6,270 = 8,810

Hence, the approximate sum = 8,810.

(iv) (4,782 + 2,345)

Round 4,782 to the nearest ten: The units digit is 2, so it rounds down to 4,780.

Round 2,345 to the nearest ten: The units digit is 5, so it rounds up to 2,350.

Approximate sum: 4,780 + 2,350 = 7,130

Hence, the approximate sum = 7,130.

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