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Mathematics

Find the area of a square plot of land whose each side measures 8128\dfrac{1}{2} metres.

[Hint: Area of the plot = side2 = (812)2\left(8\dfrac{1}{2}\right)^2 sq. m = (812×812)\left(8\dfrac{1}{2} \times 8\dfrac{1}{2}\right) sq. m]

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Answer

We know that area of a square = side × side.

Side of the square plot =812 m=172 m= 8\dfrac{1}{2} \text{ m} = \dfrac{17}{2} \text{ m}

Finding the area,

172×172=17×172×2=2894=7214 sq. m\dfrac{17}{2} \times \dfrac{17}{2} = \dfrac{17 \times 17}{2 \times 2} \\[1em] = \dfrac{289}{4} \\[1em] = 72\dfrac{1}{4} \text{ sq. m}

Hence, the area of the square plot is 7214 sq. m\mathbf{72\dfrac{1}{4} \text{ sq. m}}.

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