Mathematics

Find the cardinal number of the following sets:

(i) A = {x | x is a consonant in the word HUNDRED}

(ii) B = {x | x is a vowel in the word DEHRADOON}

(iii) C = {x | x ∈ W and x2 < 50}

(iv) D = {x | x ∈ N and x < 1}

(v) E = {x | x is a prime number between 8 and 30}

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Answer

(i) The letters in the word HUNDRED are H, U, N, D, R, E, D. The consonants among these are H, N, D, R, D. Writing each letter only once, we get H, N, D, R.

A = {H, N, D, R}, which has 4 elements.

∴ n(A) = 4.

(ii) The letters in the word DEHRADOON are D, E, H, R, A, D, O, O, N. The vowels among these are E, A, O, O. Writing each letter only once, we get E, A, O.

B = {E, A, O}, which has 3 elements.

∴ n(B) = 3.

(iii) C = {x | x ∈ W and x2 < 50}

For x = 0, x2 = 0 < 50 ✓

For x = 1, x2 = 1 < 50 ✓

For x = 2, x2 = 4 < 50 ✓

For x = 3, x2 = 9 < 50 ✓

For x = 4, x2 = 16 < 50 ✓

For x = 5, x2 = 25 < 50 ✓

For x = 6, x2 = 36 < 50 ✓

For x = 7, x2 = 49 < 50 ✓

For x = 8, x2 = 64 > 50 ✗

C = {0, 1, 2, 3, 4, 5, 6, 7}, which has 8 elements.

∴ n(C) = 8.

(iv) D = {x | x ∈ N and x < 1}

The natural numbers are 1, 2, 3, …… There is no natural number less than 1.

D = { }, which has 0 elements.

∴ n(D) = 0.

(v) The prime numbers between 8 and 30 are 11, 13, 17, 19, 23 and 29.

E = {11, 13, 17, 19, 23, 29}, which has 6 elements.

∴ n(E) = 6.

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