Simplify :

(i) $\Big(\dfrac{2}{5} \times \dfrac{5}{8}\Big) + \Big(\dfrac{-3}{7} \times \dfrac{14}{-15}\Big)$

(ii) $\Big(\dfrac{-14}{3} \times \dfrac{-12}{7}\Big) + \Big(\dfrac{-6}{25} \times \dfrac{15}{8}\Big)$

(iii) $\Big(\dfrac{6}{25} \times \dfrac{-15}{8}\Big) - \Big(\dfrac{13}{100} \times \dfrac{-25}{26}\Big)$

(iv) $\Big(\dfrac{-14}{5} \times \dfrac{-10}{7}\Big) - \Big(\dfrac{-8}{9} \times \dfrac{3}{16}\Big)$

Find the cost of $3\dfrac{1}{3}$ kg of rice at ₹ $40\dfrac{1}{2}$ per kg.

Write the multiplicative inverse of :

(i) $\dfrac{5}{6}$

(ii) $\dfrac{-3}{7}$

(iii) -8

(iv) $\dfrac{-11}{3}$

(v) $\dfrac{-1}{8}$

Find the multiplicative inverse (or reciprocal) of each of the following rational numbers :

(i) $\dfrac{6}{25}$

(ii) $-2\dfrac{3}{11}$

(iii) $\dfrac{-8}{9}$

(iv) $\dfrac{-23}{16}$

(v) 12

(vi) $\dfrac{1}{10}$

(vii) -6

(viii) -1

(ix) $\dfrac{-1}{5}$

(x) $\dfrac{-7}{-9}$