Mathematics

Find the equation of a line which makes an angle of 60° with the positive direction of the x-axis and passes through the point P(0, –3).

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m = tan θ = tan 60° = $\sqrt3$

By point-slope form,

Equation of line : y - y₁ = m(x - x₁)

Substituting values we get,

$\Rightarrow y - (-3) = \sqrt3(x - 0) \\[1em] \Rightarrow y + 3 = \sqrt3x \\[1em] \Rightarrow \sqrt3x - y = 3.$

Hence, equation of the line is $\sqrt3x - y = 3$ .

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