Find the equation of the line, whose :

(i) slope = 2 and y-intercept = 3

(ii) slope = 5 and y-intercept = - 8

(iii) slope = - 4 and y-intercept = 2

(iv) slope = - 3 and y-intercept = - 1

(v) slope = 0 and y-intercept = - 5

(vi) slope = 0 and y-intercept = 0

(i) slope = 2 ⇒ m = 2

y-intercept = 3 ⇒ c = 3

∴ Equation is : y = mx + c

⇒ y = 2x + 3

Hence, the equation of the line is y = 2x + 3.

(ii) slope = 5 ⇒ m = 5

y-intercept = -8 ⇒ c = -8

∴ Equation is : y = mx + c

⇒ y = 5x - 8

Hence, the equation of the line is y = 5x - 8.

(iii) slope = -4 ⇒ m = -4

y-intercept = 2 ⇒ c = 2

∴ Equation is : y = mx + c

⇒ y = -4x + 2

⇒ 4x + y = 2

Hence, the equation of the line is 4x + y = 2.

(iv) slope = -3 ⇒ m = -3

y-intercept = -1 ⇒ c = -1

∴ Equation is : y = mx + c

⇒ y = -3x - 1

⇒ 3x + y + 1 = 0

Hence, the equation of the line is 3x + y + 1 = 0.

(v) slope = 0 ⇒ m = 0

y-intercept = - 5 ⇒ c = - 5

∴ Equation is : y = mx + c

⇒ y = 0 $\times$ x - 5

⇒ y + 5 = 0

Hence, the equation of the line is y + 5 = 0.

(vi) slope = 0 ⇒ m = 0

y-intercept = 0 ⇒ c = 0

∴ Equation is : y = mx + c

⇒ y = 0 $\times$ x + 0

⇒ y = 0

Hence, the equation of the line is y = 0.