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Mathematics

Find the equation of a line with x-intercept = 5 and passing through the point (4, –3).

Straight Line Eq

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Answer

When x-intercept = 5; corresponding point on the x-axis = (5, 0).

By formula,

Slope = y2−y1x2−x1\dfrac{y2 - y1}{x2 - x1}

Slope of the line through (5, 0) and (4, -3) = −3−04−5=−3−1=3\dfrac{-3 - 0}{4 - 5} = \dfrac{-3}{-1} = 3

By point-slope form,

⇒ y - y1 = m(x - x1)

⇒ y - 0 = 3(x − 5)

⇒ y = 3x - 15

⇒ 3x - y = 15.

Hence, equation of line is 3x - y = 15.

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