Find the following:

(i) $\dfrac{2}{11}$ of ₹ 715

(ii) $\dfrac{4}{9}$ of 405 kg

(iii) $\dfrac{3}{7}$ of 4 hours 40 minutes

(i) $\dfrac{2}{11}$ of ₹ 715

$\Rightarrow \dfrac{2}{11} \times 715\\[1em] \Rightarrow \dfrac{2 \times 715}{11}\\[1em] \Rightarrow 2 \times 65\\[1em] \Rightarrow ₹130$

Hence, $\dfrac{2}{11}$ of ₹ 715 = ₹ 130.

(ii) $\dfrac{4}{9}$ of 405 kg

$\Rightarrow \dfrac{4}{9} \times 405\\[1em] \Rightarrow \dfrac{4 \times 405}{9}\\[1em] \Rightarrow 4 \times 45\\[1em] \Rightarrow 180 \text{ kg}$

Hence, $\dfrac{4}{9}$ of 405 kg = 180 kg.

(iii) $\dfrac{3}{7}$ of 4 hours 40 minutes

4 hours 40 minutes = (4 × 60 + 40) minutes = (240 + 40) minutes = 280 minutes.

$\Rightarrow \dfrac{3}{7} \times 280 \text{ minutes}\\[1em] \Rightarrow \dfrac{3 \times 280}{7} \text{ minutes}\\[1em] \Rightarrow 3 \times 40 \text{ minutes}\\[1em] \Rightarrow 120 \text{ minutes}\\[1em] \Rightarrow 2 \text{ hours}$

Hence, $\dfrac{3}{7}$ of 4 hours 40 minutes = 2 hours.