Find the greatest 4-digit number which is exactly divisible by each of 8, 12 and 20.
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Find the greatest 4-digit number which is exactly divisible by each of 8, 12 and 20.

KnowledgeBoat · Accepted Answer

First, we find the LCM of 8, 12 and 20. LCM of 8, 12 and 20 = 2 × 2 × 2 × 3 × 5 = 120. The greatest 4-digit number is 9999. We divide 9999 by 120 and find the remainder. The remainder is 39. The required greatest 4-digit number = 9999 − 39 = 9960. Hence, the greatest 4-digit number divisible by 8, 12 and 20 is 9960.

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Find the greatest 4-digit number which is exactly divisible by each of 8, 12 and 20.

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