Find the HCF of 180 and 336. Hence, find their LCM.

To find HCF of 180 and 336 by division method:

$\begin{array}{l} 180\overline{\smash{\big)}336\smash{\big(}}\phantom{}1 \ \phantom{x}\phantom{()}\underline{-180} \ \phantom{{x^2 } 1()}156\overline{\smash{\big)}180\smash{\big(}}\phantom{}1 \ \phantom{{x} +1xa}\underline{-156} \ \phantom{{x^2 a} + 2x()} 24\overline{\smash{\big)}156\smash{\big(}}\phantom{}6 \ \phantom{{x} +1xa+()}\underline{-144} \ \phantom{{x^2 a} + 2x++()} 12\overline{\smash{\big)}24\smash{\big(}}\phantom{}2 \ \phantom{{x} +1xa++++}\underline{-24} \ \phantom{{x^2 a} + 2x++++()} 0 \ \end{array}$

So, HCF of 180 and 336 = 12.

Now, LCM = $\dfrac{\text{Product of numbers}}{\text{HCF}}$

⇒ LCM = $\dfrac{180 \times 336}{12}$

⇒ LCM = 180 × 28

⇒ LCM = 5040.

Hence, HCF = 12 and LCM = 5040.