Find the largest three-digit number which is exactly divisible by 47

The largest three-digit number = 999.

To find the largest three-digit number exactly divisible by 47, we divide 999 by 47 and subtract the remainder from 999.

$\begin{array}{l} \phantom{x^2 }{\quad 21} \ 47\overline{\smash{\big)}999} \ \phantom{x}\phantom{}\underline{-94} \ \phantom{{x^2 }(()} 59 \ \phantom{{x}()}\underline{-47} \ \phantom{{x^2 +)}} 12 \ \end{array}$

The remainder when 999 is divided by 47 is 12.

Therefore, 999 - 12 = 987.

Hence, the largest three-digit number which is exactly divisible by 47 is 987.