Mathematics
Answer
(i) 48, 60
| 2 | 48, 60 |
|---|---|
| 2 | 24, 30 |
| 2 | 12, 15 |
| 2 | 6, 15 |
| 3 | 3, 15 |
| 5 | 1, 5 |
| 1, 1 |
Hence, LCM of 48 and 60 = 2 × 2 × 2 × 2 × 3 × 5 = 240.
(ii) 112, 168, 266
| 2 | 112, 168, 266 |
|---|---|
| 2 | 56, 84, 133 |
| 2 | 28, 42, 133 |
| 2 | 14, 21, 133 |
| 3 | 7, 21, 133 |
| 7 | 7, 7, 133 |
| 19 | 1, 1, 19 |
| 1, 1, 1 |
Hence, LCM of 112, 168 and 266 = 2 × 2 × 2 × 2 × 3 × 7 × 19 = 6384.
Related Questions
Find the HCF of the given numbers by division method:
(i) 54, 82
(ii) 84, 120, 156
Find the LCM of the given numbers by prime factorisation method:
(i) 27, 90
(ii) 36, 48, 210
Find the greatest number which divides 2706, 7041 and 8250 leaving remainder 6, 21 and 42 respectively.
Find the least number which on decreasing by 20 is exactly divisible by 18, 21, 28 and 30.