Mathematics
Find the least number which when divided by 6, 15 and 18 leaves remainder 5 in each case.
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Answer
First, we find the LCM of 6, 15 and 18.
| 2 | 6, 15, 18 |
|---|---|
| 3 | 3, 15, 9 |
| 3 | 1, 5, 3 |
| 5 | 1, 5, 1 |
| 1, 1, 1 |
LCM of 6, 15 and 18 = 2 × 3 × 3 × 5 = 90.
Thus, 90 is the least number exactly divisible by 6, 15 and 18.
The required least number which leaves remainder 5 when divided by these numbers = 90 + 5 = 95.
Hence, the required least number is 95.
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