Find the least number of five digits which is exactly divisible by 32, 36 and 45.
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Find the least number of five digits which is exactly divisible by 32, 36 and 45.

KnowledgeBoat · Accepted Answer

First, we find the LCM of 32, 36 and 45. LCM of 32, 36 and 45 = 2 × 2 × 2 × 2 × 2 × 3 × 3 × 5 = 1440. The smallest 5-digit number is 10000. We divide 10000 by 1440 and find the remainder. The remainder is 1360. The required least 5-digit number = 10000 + (1440 − 1360) = 10000 + 80 = 10080. Hence, the least 5-digit number divisible by 32, 36 and 45 is 10080.

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Find the least number of five digits which is exactly divisible by 32, 36 and 45.

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