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Mathematics

Find the mean of each of the following sets of numbers :

(i) 10, 4, 6, 12, 9

(ii) 0.2, 0.02, 2, 2.02, 1.22, 1.02

Measures of Central Tendency

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Answer

(i) Given,

10, 4, 6, 12, 9

We know that,

Mean = ∑xin\dfrac{\sum x_i}{n}

Substitute values, we get:

⇒Mean=10+4+6+12+95=415=8.2\Rightarrow \text{Mean} = \dfrac{10 + 4 + 6 + 12 + 9}{5} \\[1em] = \dfrac{41}{5} \\[1em] = 8.2

Hence, mean of given numbers = 8.2.

(ii) Given,

0.2, 0.02, 2, 2.02, 1.22, 1.02

We know that,

Mean = ∑xin\dfrac{\sum x_i}{n}

Substitute values, we get:

⇒Mean=0.2+0.02+2+2.02+1.22+1.026=6.486=1.08.\Rightarrow \text{Mean} = \dfrac{0.2 + 0.02 + 2 + 2.02 + 1.22 + 1.02}{6} \\[1em] = \dfrac{6.48}{6} \\[1em] = 1.08.

Hence, mean of given numbers = 1.08.

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