KnowledgeBoat Logo
|

Mathematics

Find the median for the following distribution:

Wages per day (in ₹)No. of workers
38014
4508
4807
55010
6206
6502

Measures of Central Tendency

13 Likes

Answer

The given variates (wages) are already in ascending order. We construct the cumulative frequency table as under :

Wages per day (in ₹)Frequency (No. of workers)Cumulative frequency (fi)
3801414
450822
480729
5501039
620645
680247

Here, n (total no. of workers) = 47, which is odd.

Median =(n+12)th observation=(47+12)th observation=(482)th observation=24th observation\text{Median }= \Big(\dfrac{n + 1}{2}\Big)\text{th observation}\\[1em] = \Big(\dfrac{47 + 1}{2}\Big)\text{th observation}\\[1em] = \Big(\dfrac{48}{2}\Big)\text{th observation}\\[1em] = 24\text{th observation}\\[1em]

All observations from 23rd to 29th are equal, each = 480.

Median = ₹480

Hence, median = ₹480.

Answered By

7 Likes


Related Questions