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Mathematics

Find the median of the following frequency distribution:

VariateFrequency
175
209
153
224
3010
256

Measures of Central Tendency

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Answer

The given varieties are arranged in ascending order.

Cumulative frequency distribution table :

VariateFrequencyCumulative frequency
1533
1758 (3 + 5)
20917 (8 + 9)
22421 (17 + 4)
25627 (21 + 6)
301037 (27 + 10)

Here number of observations, n = 37, which is odd.

By formula,

Median=37+12th observationMedian=382th observationMedian=19 th observation\Rightarrow \text{Median} = \dfrac{37 + 1}{2} \text{th} \text{ observation} \\[1em] \Rightarrow \text{Median} = \dfrac{38}{2} \text{th} \text{ observation} \\[1em] \Rightarrow \text{Median} = 19 \text{ th} \text{ observation}

From the above table, variate corresponding to a cumulative frequency from 18th to 21st are 22.

∴ 19th observation = 22.

Hence, median = 22.

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