Find points on the x-axis which are at a distance of 5 units from the point (5, -4).

We know that, y-coordinate of any point on x-axis = 0. Let point on x-axis which is at a distance of 5 units from (5, -4) be P(x, 0). By distance formula, On squaring both sides, ∴ P = (x, 0) = (2, 0) or (8, 0). Hence, points on the x-axis which are at a distance of 5 units from the point (5, -4) are (2, 0) or (8, 0).