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Mathematics

Find the product :

714×758×111217\dfrac{1}{4}\times\dfrac{7}{58}\times1\dfrac{11}{21}

Fractions

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Answer

We have:

=714×758×11121=294×758×3221[Converting mixed fraction to improper fraction]=14×72×3221[Simplifying 29 and 58 ⇒ Divide by 29 ]=14×12×323[Simplifying 7 and 21 ⇒ Divide by 7 ]=11×12×83[Simplifying 32 and 4 ⇒ Divide by 4 ]=1×1×81×2×3=86=43[Dividing both by 2]=113[Converting improper to mixed fraction]\begin{array}{ll} \phantom{=} 7\dfrac{1}{4}\times\dfrac{7}{58}\times1\dfrac{11}{21} \\ = \dfrac{29}{4} \times \dfrac{7}{58} \times \dfrac{32}{21} & \text{[Converting mixed fraction to improper fraction]} \\ = \dfrac{1}{4} \times \dfrac{7}{2} \times \dfrac{32}{21} & \text{[Simplifying 29 and 58 ⇒ Divide by 29 ]} \\ = \dfrac{1}{4} \times \dfrac{1}{2} \times \dfrac{32}{3} & \text{[Simplifying 7 and 21 ⇒ Divide by 7 ]} \\ = \dfrac{1}{1} \times \dfrac{1}{2} \times \dfrac{8}{3} & \text{[Simplifying 32 and 4 ⇒ Divide by 4 ]} \\ = \dfrac{1 \times 1 \times 8}{1 \times 2 \times 3} \\ = \dfrac{8}{6} \\ = \dfrac{4}{3} & \text{[Dividing both by 2]} \\ = 1\dfrac{1}{3} & \text{[Converting improper to mixed fraction]} \end{array}

∴ The answer is 1131\dfrac{1}{3}

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