Find the product :

$3\dfrac{1}{6} \times 2\dfrac{3}{4} \times 2\dfrac{4}{11}$

$\Rightarrow 3\dfrac{1}{6} \times 2\dfrac{3}{4} \times 2\dfrac{4}{11}\\[1em] \Rightarrow \dfrac{19}{6} \times \dfrac{11}{4} \times \dfrac{26}{11}\\[1em] \Rightarrow \dfrac{19}{6} \times \dfrac{11}{11} \times \dfrac{26}{4} \\[1em] \Rightarrow \dfrac{19}{6} \times 1 \times \dfrac{13}{2} \\[1em] \Rightarrow \dfrac{247}{12} \\[1em] \Rightarrow 20\dfrac{7}{12}.$

Hence, $3\dfrac{1}{6} \times 2\dfrac{3}{4} \times 2\dfrac{4}{11} = 20\dfrac{7}{12}$.