Find the product:

(i) $\dfrac{2}{3} \times \dfrac{3}{10}$

(ii) $\dfrac{7}{11} \times \dfrac{5}{8}$

(iii) $-\dfrac{4}{7} \times \dfrac{5}{14}$

(i) Given, $\dfrac{2}{3} \times \dfrac{3}{10}$

$\Rightarrow \dfrac{2}{3} \times \dfrac{3}{10} \\[1em] \Rightarrow \dfrac{2 \times 3}{3 \times 10} \\[1em] \Rightarrow \dfrac{6}{30} \\[1em] \Rightarrow \dfrac{1}{5}.$

Hence, $\dfrac{2}{3} \times \dfrac{3}{10} = \dfrac{1}{5}$.

(ii) Given, $\dfrac{7}{11} \times \dfrac{5}{8}$

$\Rightarrow \dfrac{7}{11} \times \dfrac{5}{8} \\[1em] \Rightarrow \dfrac{7 \times 5}{11 \times 8} \\[1em] \Rightarrow \dfrac{35}{88}.$

Hence, $\dfrac{7}{11} \times \dfrac{5}{8} = \dfrac{35}{88}$.

(iii) Given, $-\dfrac{4}{7} \times \dfrac{5}{14}$

$\Rightarrow -\dfrac{4}{7} \times \dfrac{5}{14} \\[1em] \Rightarrow -\dfrac{4 \times 5}{7 \times 14} \\[1em] \Rightarrow -\dfrac{20}{98} \\[1em] \Rightarrow -\dfrac{10}{49}.$

Hence, $-\dfrac{4}{7} \times \dfrac{5}{14} = -\dfrac{10}{49}$.