Find the quotient:
(i) 23÷310\dfrac{2}{3} \div \dfrac{3}{10}32÷103
(ii) 711÷58\dfrac{7}{11} \div \dfrac{5}{8}117÷85
(iii) −47÷514-\dfrac{4}{7} \div \dfrac{5}{14}−74÷145
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(i) Given, 23÷310\dfrac{2}{3} \div \dfrac{3}{10}32÷103
⇒23÷310⇒23×103⇒2×103×3⇒209.\Rightarrow \dfrac{2}{3} \div \dfrac{3}{10} \\[1em] \Rightarrow \dfrac{2}{3} \times \dfrac{10}{3} \\[1em] \Rightarrow \dfrac{2 \times 10}{3 \times 3} \\[1em] \Rightarrow \dfrac{20}{9}.⇒32÷103⇒32×310⇒3×32×10⇒920.
Hence, 23÷310=209\dfrac{2}{3} \div \dfrac{3}{10} = \dfrac{20}{9}32÷103=920.
(ii) Given, 711÷58\dfrac{7}{11} \div \dfrac{5}{8}117÷85
⇒711÷58⇒711×85⇒7×811×5⇒5655.\Rightarrow \dfrac{7}{11} \div \dfrac{5}{8} \\[1em] \Rightarrow \dfrac{7}{11} \times \dfrac{8}{5} \\[1em] \Rightarrow \dfrac{7 \times 8}{11 \times 5} \\[1em] \Rightarrow \dfrac{56}{55}.⇒117÷85⇒117×58⇒11×57×8⇒5556.
Hence, 711÷58=5655\dfrac{7}{11} \div \dfrac{5}{8} = \dfrac{56}{55}117÷85=5556.
(iii) Given, −47÷514-\dfrac{4}{7} \div \dfrac{5}{14}−74÷145
⇒−47÷514⇒−47×145⇒−4×147×5⇒−5635⇒−85.\Rightarrow -\dfrac{4}{7} \div \dfrac{5}{14} \\[1em] \Rightarrow -\dfrac{4}{7} \times \dfrac{14}{5} \\[1em] \Rightarrow -\dfrac{4 \times 14}{7 \times 5} \\[1em] \Rightarrow -\dfrac{56}{35} \\[1em] \Rightarrow -\dfrac{8}{5}.⇒−74÷145⇒−74×514⇒−7×54×14⇒−3556⇒−58.
Hence, −47÷514=−85-\dfrac{4}{7} \div \dfrac{5}{14} = -\dfrac{8}{5}−74÷145=−58.
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Find the difference:
(i) 56−14\dfrac{5}{6} - \dfrac{1}{4}65−41
(ii) 118−34\dfrac{11}{8} - \dfrac{3}{4}811−43
(iii) −79−(−23)-\dfrac{7}{9} - \left(-\dfrac{2}{3}\right)−97−(−32)
Find the product:
(i) 23×310\dfrac{2}{3} \times \dfrac{3}{10}32×103
(ii) 711×58\dfrac{7}{11} \times \dfrac{5}{8}117×85
(iii) −47×514-\dfrac{4}{7} \times \dfrac{5}{14}−74×145
Show that: (12+34)×83=12×83+34×83\left(\dfrac{1}{2} + \dfrac{3}{4}\right) \times \dfrac{8}{3} = \dfrac{1}{2} \times \dfrac{8}{3} + \dfrac{3}{4} \times \dfrac{8}{3}(21+43)×38=21×38+43×38.
Simplify the following using the distributive property: 79(67−34)\dfrac{7}{9}\left(\dfrac{6}{7} - \dfrac{3}{4}\right)97(76−43).