Find the smallest 4-digit number which is exactly divisible by 32, 36 and 48.

Question

KnowledgeBoat · Accepted Answer

First, we find the LCM of 32, 36 and 48. LCM of 32, 36 and 48 = 2 × 2 × 2 × 2 × 2 × 3 × 3 = 288. The smallest 4-digit number is 1000. We divide 1000 by 288 and find the remainder. The remainder is 136. The required smallest 4-digit number = 1000 + (288 − 136) = 1000 + 152 = 1152. Hence, the smallest 4-digit number divisible by 32, 36 and 48 is 1152.

Mathematics

Find the smallest 4-digit number which is exactly divisible by 32, 36 and 48.

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