Find the sum:

$\dfrac{-7}{17} + \dfrac{6}{17}$

Both rational numbers have the same (positive) denominator 17, so add the numerators keeping the denominator the same.

$\dfrac{-7}{17} + \dfrac{6}{17} = \dfrac{(-7) + 6}{17} \\[1em] = \dfrac{-1}{17}$

Hence, $\mathbf{\dfrac{-7}{17} + \dfrac{6}{17} = \dfrac{-1}{17}}$.