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Mathematics

Find the 9th term of the series :

1, 4, 16, 64, ……..

GP

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Answer

Since,

41=164=4\dfrac{4}{1} = \dfrac{16}{4} = 4.

Hence, the above sequence is a G.P. with r = 4 and a = 1.

We know that nth term of G.P.,

an = arn - 1

a9 = 1.(4)9 - 1

= (4)8

= 65536.

Hence, 9th term of the series = 65536.

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