Find the area and the perimeter of a rectangular piece of land with length $7\dfrac{2}{5}$ m and breadth $4\dfrac{1}{6}$ m.

Length = $7\dfrac{2}{5}$ m = $\dfrac{37}{5}$ m

Breadth = $4\dfrac{1}{6}$ = $\dfrac{25}{6}$m

Area = length x breadth

$= \dfrac{37}{5} \times \dfrac{25}{6}\\[1em] = \dfrac{37 \times 25}{5 \times 6}\\[1em] = \dfrac{925}{30}\\[1em] = \dfrac{185}{6}\\[1em] = 30\dfrac{5}{6} \text{ m}^2$

Perimeter = 2 x (length + breadth)

$= 2 \times \Big(\dfrac{37}{5} + \dfrac{25}{6}\Big)\\[1em]$

LCM of 5 and 6 is 2 x 3 x 5 = 30.

$= 2 \times \Big(\dfrac{37 \times 6}{5 \times 6} + \dfrac{25 \times 5}{6 \times 5}\Big)\\[1em] = 2 \times \Big(\dfrac{222}{30} + \dfrac{125}{30}\Big)\\[1em] = 2 \times \Big(\dfrac{222 + 125}{30}\Big)\\[1em] = 2 \times \Big(\dfrac{347}{30}\Big)\\[1em] = \Big(\dfrac{347 \times 2}{30 \times 1}\Big)\\[1em] = \Big(\dfrac{694}{30}\Big)\\[1em] = \Big(\dfrac{347}{15}\Big)\\[1em] = 23\Big(\dfrac{2}{15}\Big)$

Area = $30\dfrac{5}{6}$ m² and perimeter = $23\dfrac{2}{15}$ m